Let and
be any two points in a plane and let
be a vector
normal to the plane. Since
is perpendicular to
, their
dot product
is equal to
. The vector form of the plane equation through
with normal
is given by
Substituting the above equations in (0.1),
where
Equation (0.6) is the coordinate form, also called the
rectangular Cartesian co-ordinate form of plane equation. The
coefficients of
in any equation of a plane are the components
of vector normal to the plane.
Consider equation (0.6). It can be written as
Let
Then
Since in equation(0.9) are the intercepts of
respectively, i.e. the plane intersects the coordinate axes
at points
, it is called the
intercept form of the equation of plane.
Another vector form of equation of plane
Let be points in an affine space that are not collinear. Then
the plane defined by
is a set of points
,
where
. Let
be any general point in the
plane. Then
is another vector form of equation of plane. Substituting the values in equation (0.10), we get the following set of equations
Parametric form of equation of plane
The parametric form of equation of plane through points
and parameters
is obtained by equating like-terms in equation
(0.13).
Coordinate form of equation of plane in matrix form
In the figure above, is a vector perpendicular
to the plane and
lies on the plane.
Equation (0.17) is another vector form of equation of plane. Substituting the corresponding values in this equation, we get the coordinate form of equation of plane in the matrix form.
are perpendicular to each other.
is the equation of the plane through and perpendicular to
·
Since lies on the plane, the coordinates atisfy the equation of the plane.
So solving for
,
0.26 is the equation of the plane.
The coordinate form of equation of plane is obtzined by solving the equation below.